5-6[2t-2(t+3)]=8+t

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Solution for 5-6[2t-2(t+3)]=8+t equation:


Simplifying
5 + -6[2t + -2(t + 3)] = 8 + t

Reorder the terms:
5 + -6[2t + -2(3 + t)] = 8 + t
5 + -6[2t + (3 * -2 + t * -2)] = 8 + t
5 + -6[2t + (-6 + -2t)] = 8 + t

Reorder the terms:
5 + -6[-6 + 2t + -2t] = 8 + t

Combine like terms: 2t + -2t = 0
5 + -6[-6 + 0] = 8 + t
5 + -6[-6] = 8 + t

Multiply -6 * -6
5 + 36 = 8 + t

Combine like terms: 5 + 36 = 41
41 = 8 + t

Solving
41 = 8 + t

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-1t' to each side of the equation.
41 + -1t = 8 + t + -1t

Combine like terms: t + -1t = 0
41 + -1t = 8 + 0
41 + -1t = 8

Add '-41' to each side of the equation.
41 + -41 + -1t = 8 + -41

Combine like terms: 41 + -41 = 0
0 + -1t = 8 + -41
-1t = 8 + -41

Combine like terms: 8 + -41 = -33
-1t = -33

Divide each side by '-1'.
t = 33

Simplifying
t = 33

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